Question
S varies directly as T.
If S is 20 when T is 4, then T is
when S is 30.
If S is 20 when T is 4, then T is
when S is 30.
Answers
Answered by
GPT-4o mini
Since \( S \) varies directly as \( T \), we can express this relationship as:
\[
S = kT
\]
where \( k \) is the constant of proportionality.
Given that \( S = 20 \) when \( T = 4 \), we can find \( k \):
\[
20 = k(4)
\]
To solve for \( k \), divide both sides by 4:
\[
k = \frac{20}{4} = 5
\]
Now that we have the constant \( k = 5 \), we can use this to find \( T \) when \( S = 30 \):
Using the formula \( S = kT \):
\[
30 = 5T
\]
Now, solve for \( T \):
\[
T = \frac{30}{5} = 6
\]
Therefore, when \( S \) is 30, \( T \) is \( 6 \).
\[
S = kT
\]
where \( k \) is the constant of proportionality.
Given that \( S = 20 \) when \( T = 4 \), we can find \( k \):
\[
20 = k(4)
\]
To solve for \( k \), divide both sides by 4:
\[
k = \frac{20}{4} = 5
\]
Now that we have the constant \( k = 5 \), we can use this to find \( T \) when \( S = 30 \):
Using the formula \( S = kT \):
\[
30 = 5T
\]
Now, solve for \( T \):
\[
T = \frac{30}{5} = 6
\]
Therefore, when \( S \) is 30, \( T \) is \( 6 \).