Your trig function part of your equation has no variable, so H(t) is a constant value of 18.38
Do you have a typo?
Assuming there is a variable t in there somewhere, the max value would be 18+6 or 24
and the minimum would be 18-6 = 12
Since I don't know your "angle" I cannot determine when that would happen
the temperature in degree celcius in a factory during the course of a working day from 6am to 10pm, can be modelled by the function
H(t)=18+6sin(pi/8-5pi/4)for6< t < 22
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where t is the time in hours on 24 hour clock.
what are the highest and lowest temp. during the working day.
1 answer
1 answer