To solve the factored quadratic equation \((13x + 3)(9x - 14) = 0\), we can set each factor equal to zero:
- \(13x + 3 = 0\)
- \(9x - 14 = 0\)
For the first equation: \[ 13x + 3 = 0 \ 13x = -3 \ x = -\frac{3}{13} \]
For the second equation: \[ 9x - 14 = 0 \ 9x = 14 \ x = \frac{14}{9} \]
Now we can write the solution set:
\[ x = \left{-\frac{3}{13}, \frac{14}{9}\right} \]
Therefore, the correct response is:
The solution set is \( x = \left{-\frac{3}{13}, \frac{14}{9}\right} \).