Complete the square to re-write the quadratic function in vertex form:

y, equals, minus, 3, x, squared, minus, 54, x, minus, 236
y=−3x
2
−54x−236

1 answer

To complete the square for the quadratic function \( y = -3x^2 - 54x - 236 \), we will follow these steps:

  1. Factor out the coefficient of \( x^2 \) from the first two terms: \[ y = -3(x^2 + 18x) - 236 \]

  2. Complete the square inside the parentheses. To do this, take half of the coefficient of \( x \) (which is \( 18 \)), square it, and then add and subtract it inside the parentheses:

    • Half of \( 18 \) is \( 9 \), and \( 9^2 = 81 \).

    So, we rewrite the equation as: \[ y = -3(x^2 + 18x + 81 - 81) - 236 \]

  3. Rewrite it: \[ y = -3((x + 9)^2 - 81) - 236 \]

  4. Distribute the \(-3\): \[ y = -3(x + 9)^2 + 243 - 236 \]

  5. Combine the constant terms: \[ y = -3(x + 9)^2 + 7 \]

Now, we have rewritten the equation in vertex form. The vertex form of the quadratic function is: \[ y = a(x - h)^2 + k \] where \((h, k)\) is the vertex.

For this function, we have: \[ y = -3(x + 9)^2 + 7 \]

The vertex is \((-9, 7)\).