Which of these points, (2,3) , (4,5) , (−2,−5) , and (0,2) , belongs to the solution of y<3x−5

1 answer

To determine which of the points \((2,3)\), \((4,5)\), \((-2,-5)\), and \((0,2)\) satisfies the inequality \(y < 3x - 5\), we need to plug in the \(x\) and \(y\) values of each point into the inequality and see if it holds true.

  1. For \((2, 3)\): \[ y < 3x - 5 \implies 3 < 3(2) - 5 \implies 3 < 6 - 5 \implies 3 < 1 \quad \text{(False)} \]

  2. For \((4, 5)\): \[ y < 3x - 5 \implies 5 < 3(4) - 5 \implies 5 < 12 - 5 \implies 5 < 7 \quad \text{(True)} \]

  3. For \((-2, -5)\): \[ y < 3x - 5 \implies -5 < 3(-2) - 5 \implies -5 < -6 - 5 \implies -5 < -11 \quad \text{(False)} \]

  4. For \((0, 2)\): \[ y < 3x - 5 \implies 2 < 3(0) - 5 \implies 2 < 0 - 5 \implies 2 < -5 \quad \text{(False)} \]

The only point that satisfies \(y < 3x - 5\) is \((4, 5)\).