For each ordered pair (x, y), determine whether it is a solution to the inequality 6x + 5y < 2.

(7, -8)
(-4, -3)
(2, 0)
(-8, 6)

1 answer

To determine if each ordered pair \((x, y)\) is a solution to the inequality \(6x + 5y < 2\), we will substitute the values of \(x\) and \(y\) into the inequality and check if the resulting statement is true.

  1. For \((7, -8)\): \[ 6(7) + 5(-8) = 42 - 40 = 2 \] We need to check if \(2 < 2\). This is false.

  2. For \((-4, -3)\): \[ 6(-4) + 5(-3) = -24 - 15 = -39 \] We check if \(-39 < 2\). This is true.

  3. For \((2, 0)\): \[ 6(2) + 5(0) = 12 + 0 = 12 \] We check if \(12 < 2\). This is false.

  4. For \((-8, 6)\): \[ 6(-8) + 5(6) = -48 + 30 = -18 \] We check if \(-18 < 2\). This is true.

Summary of results:

  • \((7, -8)\): Not a solution
  • \((-4, -3)\): A solution
  • \((2, 0)\): Not a solution
  • \((-8, 6)\): A solution