To determine if each ordered pair \((x, y)\) is a solution to the inequality \(6x + 5y < 2\), we will substitute the values of \(x\) and \(y\) into the inequality and check if the resulting statement is true.
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For \((7, -8)\): \[ 6(7) + 5(-8) = 42 - 40 = 2 \] We need to check if \(2 < 2\). This is false.
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For \((-4, -3)\): \[ 6(-4) + 5(-3) = -24 - 15 = -39 \] We check if \(-39 < 2\). This is true.
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For \((2, 0)\): \[ 6(2) + 5(0) = 12 + 0 = 12 \] We check if \(12 < 2\). This is false.
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For \((-8, 6)\): \[ 6(-8) + 5(6) = -48 + 30 = -18 \] We check if \(-18 < 2\). This is true.
Summary of results:
- \((7, -8)\): Not a solution
- \((-4, -3)\): A solution
- \((2, 0)\): Not a solution
- \((-8, 6)\): A solution