Question

What is the product of 66 and 3, square root of, 28, end square root3
28
​
in simplest radical form?

Answer 1

To find the product of \( 66 \) and \( 3\sqrt{28} \) in simplest radical form, we can first calculate the product of the numbers individually.

1. **Calculate \( 66 \times 3 \)**:
\[
66 \times 3 = 198
\]

2. **Now, simplify \( \sqrt{28} \)**:
\[
\sqrt{28} = \sqrt{4 \times 7} = \sqrt{4} \times \sqrt{7} = 2\sqrt{7}
\]

3. **Multiply \( 198 \) by \( \sqrt{28} \) (which simplifies to \( 2\sqrt{7} \))**:
\[
198 \times \sqrt{28} = 198 \times 2\sqrt{7} = 396\sqrt{7}
\]

Thus, the product of \( 66 \) and \( 3\sqrt{28} \) in simplest radical form is:
\[
\boxed{396\sqrt{7}}
\]