Asked by shmunklee
                A function is shown.
What is the value of `f\left(-4\right)?` the function is f(x) = 10 - 4x
            
        What is the value of `f\left(-4\right)?` the function is f(x) = 10 - 4x
Answers
                    Answered by
            shmunklee
            
    A function is shown.
What is the value of `f\left(5\right)?` the function is f(x) = -3 + 8x^2
    
What is the value of `f\left(5\right)?` the function is f(x) = -3 + 8x^2
                    Answered by
            GPT-4o mini
            
    To find the value of \( f(-4) \) for the function \( f(x) = 10 - 4x \), we substitute \( -4 \) for \( x \) in the function:
\[
f(-4) = 10 - 4(-4)
\]
Next, we calculate \( 4(-4) \):
\[
4(-4) = -16
\]
Now substitute back into the equation:
\[
f(-4) = 10 + 16
\]
Finally, calculate the sum:
\[
f(-4) = 26
\]
Thus, the value of \( f(-4) \) is \( \boxed{26} \).
    
\[
f(-4) = 10 - 4(-4)
\]
Next, we calculate \( 4(-4) \):
\[
4(-4) = -16
\]
Now substitute back into the equation:
\[
f(-4) = 10 + 16
\]
Finally, calculate the sum:
\[
f(-4) = 26
\]
Thus, the value of \( f(-4) \) is \( \boxed{26} \).
                    Answered by
            GPT-4o mini
            
    To find the value of \( f(5) \) for the function \( f(x) = -3 + 8x^2 \), we substitute \( 5 \) for \( x \) in the function:
\[
f(5) = -3 + 8(5^2)
\]
First, calculate \( 5^2 \):
\[
5^2 = 25
\]
Next, substitute that value back into the equation:
\[
f(5) = -3 + 8(25)
\]
Now, calculate \( 8(25) \):
\[
8(25) = 200
\]
Now, substitute this value back into the equation:
\[
f(5) = -3 + 200
\]
Finally, calculate the sum:
\[
f(5) = 197
\]
Thus, the value of \( f(5) \) is \( \boxed{197} \).
    
\[
f(5) = -3 + 8(5^2)
\]
First, calculate \( 5^2 \):
\[
5^2 = 25
\]
Next, substitute that value back into the equation:
\[
f(5) = -3 + 8(25)
\]
Now, calculate \( 8(25) \):
\[
8(25) = 200
\]
Now, substitute this value back into the equation:
\[
f(5) = -3 + 200
\]
Finally, calculate the sum:
\[
f(5) = 197
\]
Thus, the value of \( f(5) \) is \( \boxed{197} \).
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