Question
Question 10
What is the gravitational force of attraction between a planet and a 17-kilogram mass that is freely falling toward the surface of the planet at 8.8 m/s2?
a
150 N
b
1.9 N
c
0.52 N
d
8.8 N
What is the gravitational force of attraction between a planet and a 17-kilogram mass that is freely falling toward the surface of the planet at 8.8 m/s2?
a
150 N
b
1.9 N
c
0.52 N
d
8.8 N
Answers
GPT-4o mini
To find the gravitational force of attraction between the planet and the 17-kilogram mass, we can use the formula for gravitational force:
\[ F = m \cdot g \]
Where:
- \( F \) is the gravitational force (in Newtons),
- \( m \) is the mass (in kilograms),
- \( g \) is the acceleration due to gravity (in m/s²).
In this case:
- \( m = 17 \, \text{kg} \)
- \( g = 8.8 \, \text{m/s}^2 \)
Now we can substitute the values into the equation:
\[ F = 17 \, \text{kg} \cdot 8.8 \, \text{m/s}^2 \]
Calculating this:
\[ F = 149.6 \, \text{N} \]
Rounding this to the nearest whole number gives us:
\[ F \approx 150 \, \text{N} \]
Therefore, the gravitational force of attraction between the planet and the 17-kilogram mass is approximately **150 N**.
The correct answer is:
**a 150 N**.
\[ F = m \cdot g \]
Where:
- \( F \) is the gravitational force (in Newtons),
- \( m \) is the mass (in kilograms),
- \( g \) is the acceleration due to gravity (in m/s²).
In this case:
- \( m = 17 \, \text{kg} \)
- \( g = 8.8 \, \text{m/s}^2 \)
Now we can substitute the values into the equation:
\[ F = 17 \, \text{kg} \cdot 8.8 \, \text{m/s}^2 \]
Calculating this:
\[ F = 149.6 \, \text{N} \]
Rounding this to the nearest whole number gives us:
\[ F \approx 150 \, \text{N} \]
Therefore, the gravitational force of attraction between the planet and the 17-kilogram mass is approximately **150 N**.
The correct answer is:
**a 150 N**.