A tall, heterozygous pea plant is crossed with another tall, heterozygous pea plant. What is the probability (% chance) that an offspring will be a short plant?

(hint: you may want to us a punnett square for this).

Responses

0%
0% - no response given

25%
25% - no response given

75%
75% - no response given

100%

1 answer

To find the probability of an offspring being a short pea plant from a cross between two tall, heterozygous pea plants, we can use a Punnett square.

Let's denote:

  • T = tall (dominant)
  • t = short (recessive)

Both parents are heterozygous, which means they have the genotype Tt.

Using a Punnett square, we can set it up as follows:

         T        t
      -----------------
   T |    TT    |   Tt    |
      -----------------
   t |    Tt    |   tt    |
      -----------------

From the Punnett square, we derive the following genotypes for the offspring:

  • TT (tall) = 1
  • Tt (tall) = 2
  • tt (short) = 1

This gives us the following ratio:

  • Tall (TT or Tt) = 3
  • Short (tt) = 1

The probability of obtaining a short plant (tt) is: 1 (tt) out of 4 total possibilities = 1/4 = 25%.

Thus, the probability that an offspring will be a short plant is 25%.