Question
Mr. Lopez began the two-way table below to display the dominant hand of the students in his first- and second-period classes.
Dominant Hands
Left-handed
Right-handed
Total
1st Period
9
28
2nd Period
5
31
Total
How many of Mr. Lopez’s second-period students are right-handed?
14
19
26
45
Dominant Hands
Left-handed
Right-handed
Total
1st Period
9
28
2nd Period
5
31
Total
How many of Mr. Lopez’s second-period students are right-handed?
14
19
26
45
Answers
GPT-4o mini
To find the number of Mr. Lopez’s second-period students that are right-handed, we can use the information provided in the two-way table.
From the table, we know the following:
- In the 2nd Period, there are 5 left-handed students.
- We also know that the total number of students for the 2nd Period can be calculated by adding the left-handed and right-handed students.
The total for the 2nd Period is the sum of left-handed and right-handed students:
\[ \text{Total for 2nd Period} = \text{Left-handed} + \text{Right-handed} \]
We need to find the total number of students in 2nd Period. It is not explicitly given, but we can derive it from the first period's data if we assume that the total number of students in both periods is known.
However, we do have the number of right-handed students by using the total number of right-handed students:
From the data we can sum up the number of students:
- 1st Period: \( 9 \, (\text{left}) + 28 \, (\text{right}) = 37 \)
- 2nd Period: \( 5 \, (\text{left}) + x \, (\text{right})\)
Adding both periods together gives:
Total left-handed: \( 9 + 5 = 14 \)
Total right-handed (let \( x \) be total in 2nd period): \( 28 + x\)
The overall total should equal the total we get from the column sums:
If we sum the totals (total from right-handed, left-handed, periods):
\[ 37 + (5 + x) = 14 + (28 + x) \]
In our case, we can also look directly at the already mentioned options. Based simply on filling out the table headers and how these options connect to the 2nd period:
Since Mr. Lopez's totals are coming from the existing options that are aligned logically with \( 5 + x = 31\):
\[ x = 31 - 5 = 26\]
So the number of right-handed students in the 2nd period is **26**.
Thus, the answer to how many of Mr. Lopez’s second-period students are right-handed is:
**26**
From the table, we know the following:
- In the 2nd Period, there are 5 left-handed students.
- We also know that the total number of students for the 2nd Period can be calculated by adding the left-handed and right-handed students.
The total for the 2nd Period is the sum of left-handed and right-handed students:
\[ \text{Total for 2nd Period} = \text{Left-handed} + \text{Right-handed} \]
We need to find the total number of students in 2nd Period. It is not explicitly given, but we can derive it from the first period's data if we assume that the total number of students in both periods is known.
However, we do have the number of right-handed students by using the total number of right-handed students:
From the data we can sum up the number of students:
- 1st Period: \( 9 \, (\text{left}) + 28 \, (\text{right}) = 37 \)
- 2nd Period: \( 5 \, (\text{left}) + x \, (\text{right})\)
Adding both periods together gives:
Total left-handed: \( 9 + 5 = 14 \)
Total right-handed (let \( x \) be total in 2nd period): \( 28 + x\)
The overall total should equal the total we get from the column sums:
If we sum the totals (total from right-handed, left-handed, periods):
\[ 37 + (5 + x) = 14 + (28 + x) \]
In our case, we can also look directly at the already mentioned options. Based simply on filling out the table headers and how these options connect to the 2nd period:
Since Mr. Lopez's totals are coming from the existing options that are aligned logically with \( 5 + x = 31\):
\[ x = 31 - 5 = 26\]
So the number of right-handed students in the 2nd period is **26**.
Thus, the answer to how many of Mr. Lopez’s second-period students are right-handed is:
**26**