A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the

Question

ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him? (1 point)
80 N
70 N
380 N
370 N

Answer 1

To calculate the net force acting on the boy, we need to consider all the forces acting on him:

1. The boy's force exerted on the ice: \( F_{\text{boy}} = 300 , \text{N} \)
2. The force exerted by his friend: \( F_{\text{friend}} = 75 , \text{N} \)
3. The drag and friction force opposing the motion: \( F_{\text{friction}} = 5 , \text{N} \)

The net force \( F_{\text{net}} \) can be calculated using the following formula:

\[ F_{\text{net}} = F_{\text{boy}} + F_{\text{friend}} - F_{\text{friction}} \]

Now substitute the values into the formula:

\[ F_{\text{net}} = 300 , \text{N} + 75 , \text{N} - 5 , \text{N} = 300 + 75 - 5 = 370 , \text{N} \]

So, the magnitude of the net force acting on him is \( \boxed{370 , \text{N}} \).