Sure! Let's go through the solution step by step for the equation \( 53x + 113 = -43 \).
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Start with the original equation:
\[ 53x + 113 = -43 \]
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Subtract \( 113 \) from both sides:
\[ 53x = -43 - 113 \]
Simplifying the right side:
\[ 53x = -156 \]
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Now, divide both sides by \( 53 \):
\[ x = \frac{-156}{53} \]
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Simplifying further:
The fraction \( \frac{-156}{53} \) can be simplified depending on whether it's reducible or not, but since \( 156 \div 53 \) does not yield an integer, we keep it as:
\[ x = -\frac{156}{53} \]
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Now let's multiply both sides by the reciprocal of \( 53 \), which is \( \frac{1}{53} \):
The formal statement would look something like:
\[ x = \left(-\frac{156}{53}\right) \cdot \left(\frac{1}{53}\right) \]
Thus, the filled-in numbers are:
- \( 53x = -156 \)
- \( x = -\frac{156}{53} \)
So to summarize:
\[ 53x + 113 = -43 \ 53x = -156 \quad \text{(Subtract 113 from both sides)} \ x = -\frac{156}{53} \quad \text{(Divide both sides by } 53\text{)} \]