Question
whats the median of the following number set, 2,4,0,2,1,2
Answers
Answer
thats not wright
Answered by
GPT-4o mini
To find the median of the number set \(2, 4, 0, 2, 1, 2\), follow these steps:
1. First, arrange the numbers in ascending order: \(0, 1, 2, 2, 2, 4\).
2. Since there are 6 numbers (an even count), the median will be the average of the two middle numbers. The middle numbers in this sorted list are the 3rd and 4th numbers, which are both \(2\).
3. Calculate the average of these two middle numbers:
\[
\text{Median} = \frac{2 + 2}{2} = \frac{4}{2} = 2
\]
Thus, the median of the set \(2, 4, 0, 2, 1, 2\) is \(2\).
1. First, arrange the numbers in ascending order: \(0, 1, 2, 2, 2, 4\).
2. Since there are 6 numbers (an even count), the median will be the average of the two middle numbers. The middle numbers in this sorted list are the 3rd and 4th numbers, which are both \(2\).
3. Calculate the average of these two middle numbers:
\[
\text{Median} = \frac{2 + 2}{2} = \frac{4}{2} = 2
\]
Thus, the median of the set \(2, 4, 0, 2, 1, 2\) is \(2\).
Answered by
GPT-4o mini
Let me double-check my calculations.
The original set is: \(2, 4, 0, 2, 1, 2\).
1. First, arrange the numbers in ascending order:
\(0, 1, 2, 2, 2, 4\)
2. Since there are 6 numbers in this sorted list (an even number), the median is the average of the 3rd and 4th numbers, which are \(2\) and \(2\).
3. Calculate the average:
\[
\text{Median} = \frac{2 + 2}{2} = \frac{4}{2} = 2
\]
So, the median is indeed \(2\).
If there's a specific part you'd like clarified or a different calculation you were expecting, please let me know!
The original set is: \(2, 4, 0, 2, 1, 2\).
1. First, arrange the numbers in ascending order:
\(0, 1, 2, 2, 2, 4\)
2. Since there are 6 numbers in this sorted list (an even number), the median is the average of the 3rd and 4th numbers, which are \(2\) and \(2\).
3. Calculate the average:
\[
\text{Median} = \frac{2 + 2}{2} = \frac{4}{2} = 2
\]
So, the median is indeed \(2\).
If there's a specific part you'd like clarified or a different calculation you were expecting, please let me know!
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