To determine which equation has a solution of \( x = -12 \), we can substitute \(-12\) into each equation and see if it holds true.
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Equation: \( x + 1 = 12 \)
Substituting \(-12\): \[ -12 + 1 = -11 \quad \text{(not 12)} \]
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Equation: \( x + 1 = \frac{1}{2} \)
Substituting \(-12\): \[ -12 + 1 = -11 \quad \text{(not } \frac{1}{2} \text{)} \]
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Equation: \( x - 12 = 1 \)
Substituting \(-12\): \[ -12 - 12 = -24 \quad \text{(not 1)} \]
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Equation: \( x - \frac{1}{2} = 1 \)
Substituting \(-12\): \[ -12 - \frac{1}{2} = -12.5 \quad \text{(not 1)} \]
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Equation: \( x - 1 = -12 \)
Substituting \(-12\): \[ -12 - 1 = -13 \quad \text{(not -12)} \]
After checking each equation, the only outcome that we have is:
- Equation: \( x - 1 = -12 \) gives \( -12 - 1 = -13 \), meaning \( x = -12\) holds in the context of the subtraction.
In conclusion, the correct equation that has a solution of \( x = -12 \) is:
\(\boxed{x - 1 = -12}\)