Find the missing value for 22⋅2?=2132^{2}\cdot2^?=2^{13}2

2
⋅2
?
=2
13
.

1 answer

To find the missing value in the equation \( 22 \cdot 2^? = 2^{13} \):

Let's first express \( 22 \) in terms of powers of \( 2 \):

\[ 22 = 2 \cdot 11 \]

We can rewrite the equation as follows:

\[ 2 \cdot 11 \cdot 2^? = 2^{13} \]

This can be simplified to:

\[ 2^{1 + ?} \cdot 11 = 2^{13} \]

Now, divide both sides by \( 11 \):

\[ 2^{1 + ?} = \frac{2^{13}}{11} \]

However, since the left side must also equal a power of \( 2 \), we can rewrite \( 2^{13} \) alone (since \( 11 \) is not a power of \( 2 \)):

From \( 2^{1 + ?} \), we have:

\[ 1 + ? = 13 \]

Solving for \( ? \):

\[ ? = 13 - 1 = 12 \]

Thus, the missing value is:

\[ \boxed{12} \]