Question

A charge of 24 µC is at a location where the electric potential is 8.0 V.

What is the electric potential energy of the charge?

3.0 × 10-6 J
1.9 × 10-4 J
3.0 × 100 J
1.9 × 102 J

Answer 1

The electric potential energy (U) of a charge (q) in an electric potential (V) is given by the formula:

\[ U = qV \]

Where:
- \( q \) is the charge in coulombs
- \( V \) is the electric potential in volts

Given:
- \( q = 24 \, \mu C = 24 \times 10^{-6} \, C \)
- \( V = 8.0 \, V \)

Now, substituting the values:

\[ U = (24 \times 10^{-6} \, C)(8.0 \, V) \]

Calculating:

\[ U = 192 \times 10^{-6} \, J \]
\[ U = 1.92 \times 10^{-4} \, J \]

Thus, the electric potential energy of the charge is:

**1.9 × 10^-4 J** (This corresponds to your answer choices).