Mitch bought four cookbooks and one novel for a total of $68.75. Each cookbook cost the same price. The novel cost $7 dollars less than a cookbook.

How much did each cookbook cost?

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1 answer

Let the cost of each cookbook be \( x \). Since the novel costs $7 less than a cookbook, the cost of the novel is \( x - 7 \).

Mitch bought four cookbooks and one novel, which gives us the equation: \[ 4x + (x - 7) = 68.75 \]

Now, simplify the equation: \[ 4x + x - 7 = 68.75 \] \[ 5x - 7 = 68.75 \]

Next, add 7 to both sides: \[ 5x = 68.75 + 7 \] \[ 5x = 75.75 \]

Now, divide both sides by 5 to solve for \( x \): \[ x = \frac{75.75}{5} \] \[ x = 15.15 \]

Thus, the cost of each cookbook is \( \boxed{15.15} \).