Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Which of the following correctly uses the explicit formula, An=1/4+(n−1)⋅1/2 , to find the 9th term of the described arithmetic...Question
Which of the following correctly uses the explicit formula, An=1/4+(n−1)⋅1/2
, to find the 9th term of the described arithmetic sequence?(1 point)
Responses
834
8 Start Fraction 3 over 4 End Fraction
434
4 Start Fraction 3 over 4 End Fraction
414
4 Start Fraction 1 over 4 End Fraction
814
, to find the 9th term of the described arithmetic sequence?(1 point)
Responses
834
8 Start Fraction 3 over 4 End Fraction
434
4 Start Fraction 3 over 4 End Fraction
414
4 Start Fraction 1 over 4 End Fraction
814
Answers
Answered by
GPT-4o mini
To find the 9th term of the arithmetic sequence using the explicit formula \( A_n = \frac{1}{4} + (n-1) \cdot \frac{1}{2} \), we need to substitute \( n = 9 \) into the formula:
\[
A_9 = \frac{1}{4} + (9-1) \cdot \frac{1}{2}
\]
\[
A_9 = \frac{1}{4} + 8 \cdot \frac{1}{2}
\]
\[
A_9 = \frac{1}{4} + 4
\]
Now, we need to express 4 as a fraction with a denominator of 4:
\[
4 = \frac{16}{4}
\]
Now, we can add:
\[
A_9 = \frac{1}{4} + \frac{16}{4} = \frac{17}{4}
\]
Now, let’s convert \( \frac{17}{4} \) into a mixed number:
\[
\frac{17}{4} = 4 \frac{1}{4}
\]
So, the 9th term of the sequence \( A_9 \) is \( 4 \frac{1}{4} \).
Therefore, the correct answer is:
**414** \(4 \frac{1}{4}\)
\[
A_9 = \frac{1}{4} + (9-1) \cdot \frac{1}{2}
\]
\[
A_9 = \frac{1}{4} + 8 \cdot \frac{1}{2}
\]
\[
A_9 = \frac{1}{4} + 4
\]
Now, we need to express 4 as a fraction with a denominator of 4:
\[
4 = \frac{16}{4}
\]
Now, we can add:
\[
A_9 = \frac{1}{4} + \frac{16}{4} = \frac{17}{4}
\]
Now, let’s convert \( \frac{17}{4} \) into a mixed number:
\[
\frac{17}{4} = 4 \frac{1}{4}
\]
So, the 9th term of the sequence \( A_9 \) is \( 4 \frac{1}{4} \).
Therefore, the correct answer is:
**414** \(4 \frac{1}{4}\)
There are no human answers yet. A form for humans to post answers is coming very soon!