Oliver's work contains an error in the second row where he wrote "x−3=0" instead of "x+3=0." The correct steps using the Zero Product Property for the equation \((x+3)(x+4)=0\) should involve setting each factor equal to zero:
- \(x+3=0\)
- \(x+4=0\)
Thus, the correct values of \(x\) would be \(x=-3\) and \(x=-4\), not \(x=3\) and \(x=-4\).
The most accurate response to the question is:
No, x−3=0 in the second row should be x+3=0.