Asked by Jaz
Question
Given the center left parenthesis lower h comma lower k right parenthesis equals left parenthesis 5 comma 0 right parenthesis and radius lower r equals 3, write an equation for the circle in standard form.
(1 point)
Responses
left parenthesis x plus 5 right parenthesis squared plus y squared equals 9
Image with alt text: left parenthesis x plus 5 right parenthesis squared plus y squared equals 9
left parenthesis x minus 5 right parenthesis squared plus y squared equals 9
Image with alt text: left parenthesis x minus 5 right parenthesis squared plus y squared equals 9
left parenthesis x minus 5 right parenthesis squared plus y equals 3
Image with alt text: left parenthesis x minus 5 right parenthesis squared plus y equals 3
left parenthesis x minus 5 right parenthesis squared plus y squared equals 3
Image with alt text: left parenthesis x minus 5 right parenthesis squared plus y squared equals 3
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Given the center left parenthesis lower h comma lower k right parenthesis equals left parenthesis 5 comma 0 right parenthesis and radius lower r equals 3, write an equation for the circle in standard form.
(1 point)
Responses
left parenthesis x plus 5 right parenthesis squared plus y squared equals 9
Image with alt text: left parenthesis x plus 5 right parenthesis squared plus y squared equals 9
left parenthesis x minus 5 right parenthesis squared plus y squared equals 9
Image with alt text: left parenthesis x minus 5 right parenthesis squared plus y squared equals 9
left parenthesis x minus 5 right parenthesis squared plus y equals 3
Image with alt text: left parenthesis x minus 5 right parenthesis squared plus y equals 3
left parenthesis x minus 5 right parenthesis squared plus y squared equals 3
Image with alt text: left parenthesis x minus 5 right parenthesis squared plus y squared equals 3
Skip to navigation
Answers
Answered by
GPT-4o mini
To write the equation of a circle in standard form, you can use the formula:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
where \((h, k)\) is the center of the circle and \(r\) is the radius.
In this case, you are given:
- Center \((h, k) = (5, 0)\)
- Radius \(r = 3\)
Now, substituting these values into the formula, we have:
\[
(x - 5)^2 + (y - 0)^2 = 3^2
\]
This simplifies to:
\[
(x - 5)^2 + y^2 = 9
\]
Now, comparing this with your options, the correct equation for the circle in standard form is:
\[
\left( x - 5 \right)^2 + y^2 = 9
\]
Therefore, the correct response is:
**left parenthesis x minus 5 right parenthesis squared plus y squared equals 9**
\[
(x - h)^2 + (y - k)^2 = r^2
\]
where \((h, k)\) is the center of the circle and \(r\) is the radius.
In this case, you are given:
- Center \((h, k) = (5, 0)\)
- Radius \(r = 3\)
Now, substituting these values into the formula, we have:
\[
(x - 5)^2 + (y - 0)^2 = 3^2
\]
This simplifies to:
\[
(x - 5)^2 + y^2 = 9
\]
Now, comparing this with your options, the correct equation for the circle in standard form is:
\[
\left( x - 5 \right)^2 + y^2 = 9
\]
Therefore, the correct response is:
**left parenthesis x minus 5 right parenthesis squared plus y squared equals 9**
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