Question

2y=3x-2=0

Answer 1

The equation you provided, \(2y = 3x - 2 = 0\), seems to be a bit confusing due to the double equal sign. To clarify, let's break it down into two parts:

1. \(2y = 3x - 2\)
2. \(3x - 2 = 0\)

### Part 1: Solve for \(y\)
Starting with the first equation, we can isolate \(y\):

\[
2y = 3x - 2
\]

Dividing both sides by 2:

\[
y = \frac{3x - 2}{2}
\]

### Part 2: Solve for \(x\)
From the second part of the equation, we can set \(3x - 2 = 0\) and solve for \(x\):

\[
3x - 2 = 0
\]

Adding 2 to both sides:

\[
3x = 2
\]

Dividing by 3:

\[
x = \frac{2}{3}
\]

### Final Values
Now you have \(x = \frac{2}{3}\) and can substitute this value back into the first equation to find \(y\):

\[
y = \frac{3\left(\frac{2}{3}\right) - 2}{2}
\]

Calculating further:

\[
y = \frac{2 - 2}{2} = \frac{0}{2} = 0
\]

### Summary
The solution to the equations is:

\[
\left(x, y\right) = \left(\frac{2}{3}, 0\right)
\]