Solve for u.

5
6
u+2–u=
1
6
u
u=

1 answer

To solve the equation \( 5 + 6(u + 2 - u) = 1 + 6u \), let's simplify the equation step by step.

  1. Simplify the left side: \[ u + 2 - u = 2 \] Therefore, the left side becomes: \[ 5 + 6(2) = 5 + 12 = 17 \]

  2. Now, simplify the right side: The right side \( 1 + 6u \) remains as is.

Now we can set the two sides equal to each other: \[ 17 = 1 + 6u \]

  1. Solve for \( u \): Subtract 1 from both sides: \[ 17 - 1 = 6u \] \[ 16 = 6u \]

    Now divide both sides by 6: \[ u = \frac{16}{6} = \frac{8}{3} \]

Thus, the solution for \( u \) is: \[ u = \frac{8}{3} \]