of a mile of the way. The next day they put up markers on another 12
of a mile. What is the total distance they have completed?(1 point)
11 answers
To find the total distance of the walking path marked, you need to add the two distances together:
\[ \text{Total Distance} = \frac{78}{100} \text{ miles} + \frac{12}{100} \text{ miles} \]
Combining the fractions, we have:
\[ \text{Total Distance} = \frac{78 + 12}{100} = \frac{90}{100} = \frac{9}{10} \text{ miles} \]
Thus, the total distance they have completed is \( \frac{9}{10} \) of a mile, or 0.9 miles.
To find the sum of \(215\) and \(135\), you can simply add the two numbers together:
\[ 215 + 135 = 350 \]
However, it seems like the options provided do not include \(350\). There might have been a miscalculation. Let's consider the provided responses:
The closest number to \(350\) is \(345\).
Therefore, if you are looking for the option that is closest to the sum of \(215\) and \(135\), the answer would be 345.
To find the sum of \(2 \frac{1}{5}\) and \(1 \frac{3}{5}\), we can proceed as follows:
First, convert the mixed numbers to improper fractions:
\[ 2 \frac{1}{5} = \frac{2 \times 5 + 1}{5} = \frac{10 + 1}{5} = \frac{11}{5} \]
\[ 1 \frac{3}{5} = \frac{1 \times 5 + 3}{5} = \frac{5 + 3}{5} = \frac{8}{5} \]
Now add the improper fractions:
\[ \frac{11}{5} + \frac{8}{5} = \frac{11 + 8}{5} = \frac{19}{5} \]
Convert \( \frac{19}{5} \) back to a mixed number:
\[ 19 \div 5 = 3 \quad \text{(with a remainder of } 4\text{)} \]
So, \( \frac{19}{5} = 3 \frac{4}{5} \).
Thus, the sum of \(2 \frac{1}{5}\) and \(1 \frac{3}{5}\) is \(3 \frac{4}{5}\).
The answer from the provided options is 3 4/5.
To find the result of \( 9 \frac{1}{3} - 2 \frac{2}{3} \), we will perform the following steps:
Convert the mixed numbers to improper fractions:
\[ 9 \frac{1}{3} = \frac{9 \times 3 + 1}{3} = \frac{27 + 1}{3} = \frac{28}{3} \]
\[ 2 \frac{2}{3} = \frac{2 \times 3 + 2}{3} = \frac{6 + 2}{3} = \frac{8}{3} \]
Now subtract the improper fractions:
\[ \frac{28}{3} - \frac{8}{3} = \frac{28 - 8}{3} = \frac{20}{3} \]
Convert \( \frac{20}{3} \) back to a mixed number:
\[ 20 \div 3 = 6 \quad \text{(with a remainder of } 2\text{)} \]
So, \( \frac{20}{3} = 6 \frac{2}{3} \).
Therefore, the result of \( 9 \frac{1}{3} - 2 \frac{2}{3} \) is 6 2/3.
To find the sum of \(3 \frac{5}{7}\) and \(7 \frac{1}{2}\), we can follow these steps:
Convert the mixed numbers to improper fractions.
For \(3 \frac{5}{7}\):
\[ 3 \frac{5}{7} = \frac{3 \times 7 + 5}{7} = \frac{21 + 5}{7} = \frac{26}{7} \]
For \(7 \frac{1}{2}\):
\[ 7 \frac{1}{2} = \frac{7 \times 2 + 1}{2} = \frac{14 + 1}{2} = \frac{15}{2} \]
To add these two improper fractions, we first need a common denominator. The least common multiple of \(7\) and \(2\) is \(14\).
Now convert each fraction:
\[ \frac{26}{7} = \frac{26 \times 2}{7 \times 2} = \frac{52}{14} \]
\[ \frac{15}{2} = \frac{15 \times 7}{2 \times 7} = \frac{105}{14} \]
Now, add the two fractions:
\[ \frac{52}{14} + \frac{105}{14} = \frac{52 + 105}{14} = \frac{157}{14} \]
Convert \( \frac{157}{14} \) back to a mixed number:
\[ 157 \div 14 = 11 \quad \text{(with a remainder of } 3\text{)} \]
So, \( \frac{157}{14} = 11 \frac{3}{14} \).
Therefore, the sum of \(3 \frac{5}{7}\) and \(7 \frac{1}{2}\) is 11 3/14.
To find the difference between \(9710\) and \(614\), you can perform the subtraction:
\[ 9710 - 614 = 9096 \]
It seems that the answer \(9096\) is not present in the provided options. Based on the options:
None of these options match the correct difference of \(9096\).
If there is a specific context or if I misunderstood the numbers to subtract, please let me know. Otherwise, based on just the subtraction \(9710 - 614\), the correct difference is indeed \(9096\).
1 answer
1 answer
1 answer
9 answers