To solve and simplify \( 1925 - 425 \):
\[ 1925 - 425 = 1500 \]
So, \( 1925 - 425 = 1500 \).
Solve and simplify. 1925 − 425
9 answers
To solve and simplify \( 1925 - 425 \):
\[ 1925 - 425 = 1500 \]
So, \( 1925 - 425 = 1500 \).
To solve and simplify \( \frac{19}{25} - \frac{4}{25} \):
Since the denominators are the same, you can subtract the numerators directly:
\[ \frac{19 - 4}{25} = \frac{15}{25} \]
Now, simplify \( \frac{15}{25} \):
\[ \frac{15 \div 5}{25 \div 5} = \frac{3}{5} \]
So, \( \frac{19}{25} - \frac{4}{25} = \frac{3}{5} \).
To solve and simplify \( \frac{17}{35} - \frac{10}{35} \):
Since the denominators are the same, you can subtract the numerators directly:
\[ \frac{17 - 10}{35} = \frac{7}{35} \]
Now, simplify \( \frac{7}{35} \):
\[ \frac{7 \div 7}{35 \div 7} = \frac{1}{5} \]
So, \( \frac{17}{35} - \frac{10}{35} = \frac{1}{5} \).
To find out how much water was lost from the pool, we need to subtract the final amount of water from the initial amount.
The initial amount of water in the pool is \( \frac{3}{4} \), and the final amount is \( \frac{3}{10} \).
So we need to calculate:
\[ \frac{3}{4} - \frac{3}{10} \]
To do this, we need a common denominator. The least common multiple of 4 and 10 is 20.
Now we convert both fractions to have a denominator of 20:
\[ \frac{3}{4} = \frac{3 \times 5}{4 \times 5} = \frac{15}{20} \]
\[ \frac{3}{10} = \frac{3 \times 2}{10 \times 2} = \frac{6}{20} \]
Now we can subtract:
\[ \frac{15}{20} - \frac{6}{20} = \frac{15 - 6}{20} = \frac{9}{20} \]
So, the amount of water lost from the pool is \( \frac{9}{20} \).
The answer is \( \frac{9}{20} \).
To simplify the fraction \( \frac{6}{10} \), you need to divide both the numerator and the denominator by their greatest common divisor (GCD).
The GCD of 6 and 10 is 2.
Now, divide both the numerator and the denominator by 2:
\[ \frac{6 \div 2}{10 \div 2} = \frac{3}{5} \]
So, \( \frac{6}{10} \) simplified is \( \frac{3}{5} \).