To compare the kinetic and potential energies of Watermelon A and Watermelon B, we can use the formulas for kinetic energy (KE) and potential energy (PE).
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Kinetic Energy (KE) is calculated using the formula: \[ KE = \frac{1}{2} mv^2 \] where \( m \) is the mass in kilograms and \( v \) is the speed in meters per second.
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Potential Energy (PE) depends on the height from which the watermelons fall. Since it is not specified in the question, we can assume both watermelons have the same height at the moment they fall, which would mean they have the same potential energy.
Now let's calculate the kinetic energy for each watermelon.
For Watermelon A:
- Mass (\( m \)) = 4 kg
- Speed (\( v \)) = 2 m/s \[ KE_A = \frac{1}{2} \times 4 \times (2^2) = \frac{1}{2} \times 4 \times 4 = 8 , \text{Joules} \]
For Watermelon B:
- Mass (\( m \)) = 4 kg
- Speed (\( v \)) = 4 m/s \[ KE_B = \frac{1}{2} \times 4 \times (4^2) = \frac{1}{2} \times 4 \times 16 = 32 , \text{Joules} \]
Now we can summarize:
- Both watermelons have the same mass, thus potential energy is the same as long as they start from the same height.
- Watermelon A has a kinetic energy of 8 Joules.
- Watermelon B has a kinetic energy of 32 Joules.
Conclusion:
- Potential Energy: Both fruits have the same potential energy (assuming they are at the same height).
- Kinetic Energy: Watermelon B has more kinetic energy (32 Joules) compared to Watermelon A (8 Joules).
Based on these comparisons, the correct response is:
The watermelon B has more kinetic energy.