From your description, it sounds like you're dealing with an equation of the form \( ax^2 + bx + c = d \), where one side has a quadratic expression (like \( ax^2 + bx + c \)) and the other side is a numeric expression (like \( d \)).
Let's break down the statements given:
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If the quadratic expression is 0, there are 2 solutions.
- This is generally false. If a quadratic expression equals zero \((ax^2 + bx + c = 0)\), there can be 0, 1, or 2 solutions depending on the discriminant \( (b^2 - 4ac) \). If the discriminant is positive, there are 2 distinct solutions; if it is zero, there is 1 solution (a double root); and if it is negative, there are no real solutions.
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If the numeric expression is 0, there is one solution.
- This statement is ambiguous without context. If you set the equation equal to zero \( ax^2 + bx + c = 0 \), then, similar to the first point, there can be 0, 1, or 2 solutions based on the discriminant.
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If the numeric expression is 0, there are no solutions.
- Like the previous statement, this is also ambiguous. If you set it equal to zero, it might have 0, 1, or 2 solutions depending on the details of the quadratic expression.
Based on the context, none of the statements are universally correct without additional clarification about what "New York expression" and "New American expression" mean, as it seems they could refer to different mathematical constructs.
In conclusion, since we don't have clear definitions for "New York expression" and "New American expression," we can't determine which statement, if any, is universally true. More context or clarification is needed to answer the question definitively.