Question

Solve `x^{2}-4x-5=0` and enter solutions below.

Answer 1

its wrong.. redo please

Answer 2

To solve the quadratic equation \(x^{2} - 4x - 5 = 0\), we can use the quadratic formula:

\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]

where \(a = 1\), \(b = -4\), and \(c = -5\).

First, we calculate the discriminant:

\[
b^2 - 4ac = (-4)^2 - 4(1)(-5) = 16 + 20 = 36
\]

Now we apply the quadratic formula:

\[
x = \frac{-(-4) \pm \sqrt{36}}{2(1)} = \frac{4 \pm 6}{2}
\]

This gives us two possible solutions:

1. \(x = \frac{4 + 6}{2} = \frac{10}{2} = 5\)
2. \(x = \frac{4 - 6}{2} = \frac{-2}{2} = -1\)

Thus, the solutions to the equation \(x^{2} - 4x - 5 = 0\) are:

\[
x = 5 \quad \text{and} \quad x = -1
\]

The final answer is:

\(x = 5, -1\)