Question
if a car starts at rest and accelerates to 40 m/s in a time of 10 s. What is the acceleration of the car?
\large acceleration=\frac{v_{final}-v_{initial}}{time}
a
4 m/s2
b
4 m/s
c
-4 m/s2
d
400 m/s2
\large acceleration=\frac{v_{final}-v_{initial}}{time}
a
4 m/s2
b
4 m/s
c
-4 m/s2
d
400 m/s2
Answers
GPT-4o mini
To find the acceleration of the car, we can use the formula:
\[
\text{acceleration} = \frac{v_{\text{final}} - v_{\text{initial}}}{\text{time}}
\]
Given that:
- \( v_{\text{final}} = 40 \, \text{m/s} \)
- \( v_{\text{initial}} = 0 \, \text{m/s} \) (since the car starts at rest)
- \(\text{time} = 10 \, \text{s}\)
Substituting these values into the formula, we get:
\[
\text{acceleration} = \frac{40 \, \text{m/s} - 0 \, \text{m/s}}{10 \, \text{s}} = \frac{40 \, \text{m/s}}{10 \, \text{s}} = 4 \, \text{m/s}^2
\]
Thus, the acceleration of the car is \( 4 \, \text{m/s}^2 \).
The answer is **a. 4 m/s²**.
\[
\text{acceleration} = \frac{v_{\text{final}} - v_{\text{initial}}}{\text{time}}
\]
Given that:
- \( v_{\text{final}} = 40 \, \text{m/s} \)
- \( v_{\text{initial}} = 0 \, \text{m/s} \) (since the car starts at rest)
- \(\text{time} = 10 \, \text{s}\)
Substituting these values into the formula, we get:
\[
\text{acceleration} = \frac{40 \, \text{m/s} - 0 \, \text{m/s}}{10 \, \text{s}} = \frac{40 \, \text{m/s}}{10 \, \text{s}} = 4 \, \text{m/s}^2
\]
Thus, the acceleration of the car is \( 4 \, \text{m/s}^2 \).
The answer is **a. 4 m/s²**.