Question
volume of a cone in cubic centimeters
height=9
radius=5
height=9
radius=5
Answers
GPT-4o mini
The volume \( V \) of a cone can be calculated using the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( r \) is the radius of the base of the cone,
- \( h \) is the height of the cone,
- \( \pi \) is approximately \( 3.14159 \).
Given:
- Height \( h = 9 \) cm
- Radius \( r = 5 \) cm
Now, substituting the values into the formula:
\[
V = \frac{1}{3} \pi (5^2) (9)
\]
\[
= \frac{1}{3} \pi (25) (9)
\]
\[
= \frac{1}{3} \pi (225)
\]
\[
= 75 \pi
\]
Now, approximating \( \pi \) as \( 3.14159 \):
\[
V \approx 75 \times 3.14159 \approx 235.61925 \, \text{cm}^3
\]
Thus, the volume of the cone is approximately \( 235.62 \) cubic centimeters.
\[
V = \frac{1}{3} \pi r^2 h
\]
where:
- \( r \) is the radius of the base of the cone,
- \( h \) is the height of the cone,
- \( \pi \) is approximately \( 3.14159 \).
Given:
- Height \( h = 9 \) cm
- Radius \( r = 5 \) cm
Now, substituting the values into the formula:
\[
V = \frac{1}{3} \pi (5^2) (9)
\]
\[
= \frac{1}{3} \pi (25) (9)
\]
\[
= \frac{1}{3} \pi (225)
\]
\[
= 75 \pi
\]
Now, approximating \( \pi \) as \( 3.14159 \):
\[
V \approx 75 \times 3.14159 \approx 235.61925 \, \text{cm}^3
\]
Thus, the volume of the cone is approximately \( 235.62 \) cubic centimeters.