Identify the quadrant of the point (-3, -4)?

Question

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1 point
Quadrant I
Quadrant II
Quadrant III
Quadrant IV
What are the coordinates of the point represented by the square?
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1 point
Captionless Image
(3, 4)
(-3,2)
(2, -3)
(1, -5)
What are the coordinates of Point A when reflected over the x axis?
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1 point
Captionless Image
(-2, -3)
(-3, -2)
(2, 3)
(3, 2)
Which point has a distance of 5 from the point (0, -1)?
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1 point
(5, 3)
(-5, -1)
(-1, 6)
(0, 4)
What can be the value of x, so that the ordered pair (x , 6) is located in Quadrant II?
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1 point
Captionless Image
4
-3
2
5

Answer 1

Let's answer each question one by one.

1. Identify the quadrant of the point (-3, -4):

   • The point (-3, -4) has a negative x-coordinate and a negative y-coordinate. This means it is located in Quadrant III.

2. What are the coordinates of the point represented by the square?

   • Since there is a lack of context regarding the image represented by the square, here's a brief explanation to help identify coordinates based on provided options:
     • (3, 4) – Quadrant I
     • (-3, 2) – Quadrant II
     • (2, -3) – Quadrant IV
     • (1, -5) – Quadrant IV
   • Please provide additional context or clarify the image for an accurate response.

3. What are the coordinates of Point A when reflected over the x axis?

   • When a point (x, y) is reflected over the x-axis, its coordinates become (x, -y). Therefore, without seeing the image, if Point A is, say, (-2, 3), the reflection would be (-2, -3). Without context, I can't specify the answer—please provide the point.

4. Which point has a distance of 5 from the point (0, -1)?

   • The distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula: $$d=\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}$$
   • We need to check each option against the point (0, -1):
     • (5, 3): $\sqrt{(5-0{)}^2+(3+1{)}^2}=\sqrt{25+16}=\sqrt{41}$ (not 5)
     • (-5, -1): $\sqrt{(-5-0{)}^2+(-1+1{)}^2}=\sqrt{25+0}=5$ (yes, valid)
     • (-1, 6): $\sqrt{(-1-0{)}^2+(6+1{)}^2}=\sqrt{1+49}=\sqrt{50}$ (not 5)
     • (0, 4): $\sqrt{(0-0{)}^2+(4+1{)}^2}=\sqrt{0+25}=5$ (yes, valid)
   • Valid options with a distance of 5 from (0, -1): (-5, -1) and (0, 4).

5. What can be the value of x, so that the ordered pair (x, 6) is located in Quadrant II?

   • In Quadrant II, the x-coordinate must be negative and the y-coordinate positive. Since (x, 6) is given and 6 is positive, we need x to be negative. The only available negative value from the options is -3.

If you need further clarifications or if you can provide more context for the images, I’d be happy to help!