Question

Identify the quadrant of the point (-3, -4)?
*
1 point
Quadrant I
Quadrant II
Quadrant III
Quadrant IV
What are the coordinates of the point represented by the square?
*
1 point
Captionless Image
(3, 4)
(-3,2)
(2, -3)
(1, -5)
What are the coordinates of Point A when reflected over the x axis?
*
1 point
Captionless Image
(-2, -3)
(-3, -2)
(2, 3)
(3, 2)
Which point has a distance of 5 from the point (0, -1)?
*
1 point
(5, 3)
(-5, -1)
(-1, 6)
(0, 4)
What can be the value of x, so that the ordered pair (x , 6) is located in Quadrant II?
*
1 point
Captionless Image
4
-3
2
5

Answer 1

Let's answer each question one by one.

1. **Identify the quadrant of the point (-3, -4):**
- The point (-3, -4) has a negative x-coordinate and a negative y-coordinate. This means it is located in **Quadrant III**.

2. **What are the coordinates of the point represented by the square?**
- Since there is a lack of context regarding the image represented by the square, here's a brief explanation to help identify coordinates based on provided options:
- (3, 4) – Quadrant I
- (-3, 2) – Quadrant II
- (2, -3) – Quadrant IV
- (1, -5) – Quadrant IV
- Please provide additional context or clarify the image for an accurate response.

3. **What are the coordinates of Point A when reflected over the x axis?**
- When a point (x, y) is reflected over the x-axis, its coordinates become (x, -y). Therefore, without seeing the image, if Point A is, say, (-2, 3), the reflection would be (-2, -3). Without context, I can't specify the answer—please provide the point.

4. **Which point has a distance of 5 from the point (0, -1)?**
- The distance between two points \((x_1, y_1)\) and \( (x_2, y_2)\) is given by the formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
- We need to check each option against the point (0, -1):
- (5, 3): \( \sqrt{(5 - 0)^2 + (3 + 1)^2} = \sqrt{25 + 16} = \sqrt{41} \) (not 5)
- (-5, -1): \( \sqrt{(-5 - 0)^2 + (-1 + 1)^2} = \sqrt{25 + 0} = 5 \) (yes, valid)
- (-1, 6): \( \sqrt{(-1 - 0)^2 + (6 + 1)^2} = \sqrt{1 + 49} = \sqrt{50} \) (not 5)
- (0, 4): \( \sqrt{(0 - 0)^2 + (4 + 1)^2} = \sqrt{0 + 25} = 5 \) (yes, valid)
- Valid options with a distance of 5 from (0, -1): **(-5, -1)** and **(0, 4)**.

5. **What can be the value of x, so that the ordered pair (x, 6) is located in Quadrant II?**
- In Quadrant II, the x-coordinate must be negative and the y-coordinate positive. Since (x, 6) is given and 6 is positive, we need x to be negative. The only available negative value from the options is **-3**.

If you need further clarifications or if you can provide more context for the images, I’d be happy to help!