To find the solution for the system of equations represented by the two functions \(y = x + 6\) and \(y = 2x + 3\), we can compare the y-values in the table for each corresponding x-value.
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Start with the equations:
- Equation 1: \(y = x + 6\)
- Equation 2: \(y = 2x + 3\)
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Check the given x-values and calculate the corresponding y-values for both equations:
- For \(x = 0\):
- \(y = 0 + 6 = 6\) (Equation 1)
- \(y = 2(0) + 3 = 3\) (Equation 2)
- For \(x = 1\):
- \(y = 1 + 6 = 7\) (Equation 1)
- \(y = 2(1) + 3 = 5\) (Equation 2)
- For \(x = 2\):
- \(y = 2 + 6 = 8\) (Equation 1)
- \(y = 2(2) + 3 = 7\) (Equation 2)
- For \(x = 3\):
- \(y = 3 + 6 = 9\) (Equation 1)
- \(y = 2(3) + 3 = 9\) (Equation 2)
- For \(x = 4\):
- \(y = 4 + 6 = 10\) (Equation 1)
- \(y = 2(4) + 3 = 11\) (Equation 2)
- For \(x = 0\):
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Now we can find the x-value for which the y-values from both equations are equal. From our calculations above, the only point where the y-values from both equations match is:
- When \(x = 3\):
- \(y = 9\) from both equations
- When \(x = 3\):
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Therefore, the solution to the system of equations is: \[ (x, y) = (3, 9) \]
So the final answer is: \[ \text{The solution for the system is } (3, 9). \]