Question

($) Cost of Candy Bar A Quantity 1 ($) Cost 1.25 2 2.50 3 3.75 4 5.00 5 6.25 The cost of Candy Bar A is displayed in the table. The proportional relationship between the cost and quantity for Candy Bar B is represented by the equation y = x Which candy bar is the cheapest cost per bar? Enter 1 for Candy Bar A. Enter 2 for Candy Bar B. (1 point)

Answer 1

What's the slope?
The plotted points are (0, -2) and (1, 3)

Answer 2

In slope-intercept form

Answer 3

(1, 3) and (0, -2) in slope-intercept form

Answer 4

What's the clear answer

Answer 5

Graph the linear equation y = 2x - 3

Answer 6

To determine which candy bar is cheaper per unit, we need to find the cost per candy bar for both Candy Bar A and Candy Bar B.

### Candy Bar A:
The cost for Candy Bar A is given in the table:
- Quantity 1: $1.25 → Cost per bar = $1.25
- Quantity 2: $2.50 → Cost per bar = $2.50/2 = $1.25
- Quantity 3: $3.75 → Cost per bar = $3.75/3 = $1.25
- Quantity 4: $5.00 → Cost per bar = $5.00/4 = $1.25
- Quantity 5: $6.25 → Cost per bar = $6.25/5 = $1.25

For Candy Bar A, the cost per bar is consistently $1.25.

### Candy Bar B:
The relationship for Candy Bar B is given by the equation \( y = x \). This means the cost is equal to the quantity (in dollars):
- Quantity 1: $1.00 → Cost per bar = $1.00
- Quantity 2: $2.00 → Cost per bar = $2.00/2 = $1.00
- Quantity 3: $3.00 → Cost per bar = $3.00/3 = $1.00
- Quantity 4: $4.00 → Cost per bar = $4.00/4 = $1.00
- Quantity 5: $5.00 → Cost per bar = $5.00/5 = $1.00

For Candy Bar B, the cost per bar is consistently $1.00.

### Conclusion:
Comparing the two:
- Candy Bar A: $1.25 per bar
- Candy Bar B: $1.00 per bar

Candy Bar B has the cheaper cost per bar.

So the answer is **2** for Candy Bar B.

Answer 7

To find the slope of the line that passes through the two points \((0, -2)\) and \((1, 3)\), we use the formula for the slope \(m\):

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Where:
- \((x_1, y_1) = (0, -2)\)
- \((x_2, y_2) = (1, 3)\)

Plugging in the values:

\[
m = \frac{3 - (-2)}{1 - 0} = \frac{3 + 2}{1} = \frac{5}{1} = 5
\]

Thus, the slope of the line is **5**.

Answer 8

The slope-intercept form of a linear equation is given by:

\[
y = mx + b
\]

where \(m\) is the slope and \(b\) is the y-intercept.

From the previous calculation, we found that the slope \(m\) is \(5\). We also have the y-intercept from the point \((0, -2)\), which tells us that when \(x = 0\), \(y = -2\). Therefore, the y-intercept \(b\) is \(-2\).

Now we can substitute the values of \(m\) and \(b\) into the slope-intercept form:

\[
y = 5x - 2
\]

Thus, the equation in slope-intercept form is:

\[
y = 5x - 2
\]

Answer 9

To write the equation of the line that passes through the points \((1, 3)\) and \((0, -2)\) in slope-intercept form \(y = mx + b\), we will first find the slope \(m\) and then use one of the points to find the y-intercept \(b\).

### Step 1: Find the slope \(m\)

Using the slope formula:

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Let \((x_1, y_1) = (1, 3)\) and \((x_2, y_2) = (0, -2)\):

\[
m = \frac{-2 - 3}{0 - 1} = \frac{-5}{-1} = 5
\]

### Step 2: Find the y-intercept \(b\)

Now that we have the slope \(m = 5\), we can use the y-intercept provided by point \((0, -2)\). Since when \(x = 0\), \(y = -2\), the y-intercept \(b\) is \(-2\).

### Step 3: Write the equation in slope-intercept form

Now we can substitute the values of \(m\) and \(b\) into the slope-intercept form:

\[
y = mx + b
\]

This gives us:

\[
y = 5x - 2
\]

Thus, the equation of the line in slope-intercept form that passes through the points \((1, 3)\) and \((0, -2)\) is:

\[
y = 5x - 2
\]

Answer 10

The equation of the line that passes through the points \((1, 3)\) and \((0, -2)\) in slope-intercept form is:

\[
y = 5x - 2
\]

Answer 11

To graph the linear equation \(y = 2x - 3\), follow these steps:

### 1. Identify the slope and y-intercept
The equation is in slope-intercept form \(y = mx + b\) where:
- \(m\) (slope) = 2
- \(b\) (y-intercept) = -3

This means:
- The slope of the line is 2, which indicates that for every 1 unit increase in \(x\), \(y\) increases by 2 units.
- The y-intercept is \(-3\), meaning the line intersects the y-axis at the point (0, -3).

### 2. Plot the y-intercept
Start by plotting the y-intercept (0, -3) on the graph.

### 3. Use the slope to find another point
From the y-intercept (0, -3), apply the slope of 2:
- Rise: 2 (go up 2 units)
- Run: 1 (go right 1 unit)

Starting from (0, -3):
- Move up 2 units to (1, -1)
- Move right 1 unit to (1, -1)

Now, you have another point at (1, -1) to plot.

### 4. Draw the line
Using a ruler, draw a straight line through the points (0, -3) and (1, -1). Extend the line in both directions, adding arrows to indicate it continues infinitely.

### Summary of Points
- Start point: (0, -3)
- Second point using slope: (1, -1)

You can also find additional points by substituting other values for \(x\) into the equation:

- For \(x = 2\):
\[
y = 2(2) - 3 = 4 - 3 = 1 \quad \implies (2, 1)
\]
- For \(x = -1\):
\[
y = 2(-1) - 3 = -2 - 3 = -5 \quad \implies (-1, -5)
\]

### Graph
You will have points (0, -3), (1, -1), (2, 1), and (-1, -5) to plot, which will all lie on the same line.

Unfortunately, I’m unable to create visual graphs directly, but you can use graphing software or graph paper to plot the points and draw the line based on the information provided.