Question

Of the students in Ms. Martinez's class,

walk to school and

of the students ride their bikes. How many more students from Ms. Martinez's class walk to school than ride their bikes?
Responses

A


1/8

B
1/6

C
1/24

D

1/12

Answer 1

To solve this problem, let's denote the total number of students in Ms. Martinez's class as \( N \).

Let’s assume:

- The fraction of students who walk to school is \( W \).
- The fraction of students who ride their bikes is \( R \).

According to the problem, we need to find how many more students walk to school than ride their bikes. Therefore, we need the difference \( W - R \).

However, in the question, it looks like the actual fractions are missing (represented by blank spaces). If you could provide those fractions or clarify further, I would be able to assist in calculating the difference and determining how many more students walk than ride their bikes.

Let's analyze the problem with hypothetical values:
1. If \(\frac{1}{4}\) of the students walk to school, and \(\frac{1}{6}\) ride their bikes, the computations would be as follows:

\[
W - R = \frac{1}{4} - \frac{1}{6}
\]

To calculate this, we need a common denominator:
- The least common multiple of 4 and 6 is 12.

Now we convert the fractions:

\[
\frac{1}{4} = \frac{3}{12}
\]
\[
\frac{1}{6} = \frac{2}{12}
\]

Now, we can subtract:

\[
W - R = \frac{3}{12} - \frac{2}{12} = \frac{1}{12}
\]

So in this hypothetical case, the difference would be \(\frac{1}{12}\).

If you can provide the exact fractions for students who walk and ride bikes, I can help you find the exact answer using those numbers.