Question

5. Match each ⭐ with a πŸ’Ž .
A card sort is on the screen. To start dragging a card, Tab to it and press M to mark it. Next, Tab to the card where you want to drop, and press J to join the two cards together. To unjoin the selected card from a group, press U.
3xβˆ’2 πŸ’Ž

1
x​ ⭐

3
x4​ ⭐

y3
x2​ ⭐

x2yβˆ’3 πŸ’Ž

x0 πŸ’Ž

xβˆ’2y3 πŸ’Ž

xβˆ’1 πŸ’Ž

xβˆ’3 πŸ’Ž

1
x3​ ⭐

3xβˆ’4 πŸ’Ž

3
x2​ ⭐

1 ⭐

To attach cards, drag it on TOP of each other until you see them CONNECT.



To detach, drag the BOTTOM card away.

x2
y3​

Answers

Answered by GPT-4o mini
To match each starred cards (⭐) with diamond cards (πŸ’Ž), we need to look for equivalent algebraic expressions based on exponents of \( x \) and \( y \).

Here’s how we can match them:

1. **\( \frac{1}{x} \) (⭐)** can be matched with **\( x^{-1} \) (πŸ’Ž)** because \( \frac{1}{x} = x^{-1} \).

2. **\( \frac{3}{x^4} \) (⭐)** can be matched with **\( 3x^{-4} \) (πŸ’Ž)** for the same reason: \( \frac{3}{x^4} = 3x^{-4} \).

3. **\( y^3x^2 \) (⭐)** can be matched with **\( x^2y^3 \) (πŸ’Ž)** because these two expressions are equivalent regardless of the order (commutative property of multiplication).

4. **\( x^{-2}y^3 \) (⭐)** can be matched with **\( x^{-2}y^3 \) (πŸ’Ž)** as they are the same expression.

5. **\( \frac{1}{x^3} \) (⭐)** can be matched with **\( x^{-3} \) (πŸ’Ž)** since \( \frac{1}{x^3} = x^{-3} \).

6. **\( 1 \) (⭐)** remains unmatched as there is no specific partner among diamonds that is equivalent.

7. **\( 3x^2 \) (⭐)** can also remain unmatched as there is no specific partner among diamonds that is equivalent.

Therefore, the matches are:

1. \( 1/x \) ⭐ matches (x^{-1}) πŸ’Ž
2. \( 3/x^4 \) ⭐ matches (3x^{-4}) πŸ’Ž
3. \( y^3*x^2 \) ⭐ matches (x^2*y^3) πŸ’Ž
4. \( x^{-2}y^3 \) ⭐ matches (x^{-2}y^3) πŸ’Ž
5. \( 1/x^3 \) ⭐ matches (x^{-3}) πŸ’Ž

Remaining unmatched cards are:
- \( 1 \) ⭐
- \( 3x^2 \) ⭐

You can now proceed with these matches as per the directions provided on the screen for the drag and drop action.

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