Question

An iron block has a length of 8 centimeters, a width of 5 centimeters, and a height of 4 centimeters. If the density of iron is 7,874 kg/m3 , which of the following correctly calculates the mass of the block?

Answer 1

To calculate the mass of the iron block, you can use the formula:

\[
\text{Mass} = \text{Density} \times \text{Volume}
\]

First, you need to calculate the volume of the block. The volume \( V \) of a rectangular block can be found using the formula:

\[
V = \text{Length} \times \text{Width} \times \text{Height}
\]

Given the dimensions:
- Length = 8 cm = 0.08 m
- Width = 5 cm = 0.05 m
- Height = 4 cm = 0.04 m

Now, calculate the volume:

\[
V = 0.08 \, \text{m} \times 0.05 \, \text{m} \times 0.04 \, \text{m} = 0.00016 \, \text{m}^3
\]

Next, use the density of iron, which is 7,874 kg/m³, to find the mass:

\[
\text{Mass} = \text{Density} \times \text{Volume} = 7,874 \, \text{kg/m}^3 \times 0.00016 \, \text{m}^3
\]

Now, perform this multiplication:

\[
\text{Mass} = 7,874 \times 0.00016 = 1.25984 \, \text{kg}
\]

Thus, the mass of the iron block is approximately **1.26 kg**.