Question

Enter > or < to make this statement true: 6/5⋅9/2
__ 6/5
.(1 point)

Answer 1

To solve the inequality \( \frac{6}{5} \cdot \frac{9}{2} \, __ \, \frac{6}{5} \), we first calculate \( \frac{6}{5} \cdot \frac{9}{2} \):

\[
\frac{6}{5} \cdot \frac{9}{2} = \frac{6 \cdot 9}{5 \cdot 2} = \frac{54}{10} = \frac{27}{5}
\]

Now we compare \( \frac{27}{5} \) with \( \frac{6}{5} \).

To make the comparison easier, we can convert both fractions to a common denominator or decimal:

\[
\frac{27}{5} = 5.4 \quad \text{and} \quad \frac{6}{5} = 1.2
\]

Since \( 5.4 > 1.2 \), we have:

\[
\frac{27}{5} > \frac{6}{5}
\]

Thus, the answer is:

>

The complete statement is: \( \frac{6}{5} \cdot \frac{9}{2} > \frac{6}{5} \).