Question
Chester used the regression equation of the weight loss plan to make a prediction within the given data range. Complete his work to calculate the number of weekly hours of aerobic activity needed for a monthly weight loss of 3 pounds. Round to the nearest hundredth.
1. Regression equation: y = 1.178 x + 0.71. 2. Substitute 3 for y: 3 = 1.178 x + 0.71. 3. Subtract 0.71 from both sides: 2.29 = 1.178 x. 4. Divided both sides by 1.178: StartFraction 2.29 Over 1.178 EndFraction = StartFraction 1.178 Over 1.178 EndFraction x.
About
hours of weekly aerobic activity will result in 3 pounds of monthly weight loss.
1. Regression equation: y = 1.178 x + 0.71. 2. Substitute 3 for y: 3 = 1.178 x + 0.71. 3. Subtract 0.71 from both sides: 2.29 = 1.178 x. 4. Divided both sides by 1.178: StartFraction 2.29 Over 1.178 EndFraction = StartFraction 1.178 Over 1.178 EndFraction x.
About
hours of weekly aerobic activity will result in 3 pounds of monthly weight loss.
Answers
GPT-4o mini
To complete Chester's calculations and find the number of weekly hours of aerobic activity needed for a monthly weight loss of 3 pounds, we will continue from where he left off.
1. We have the equation from his work:
\[
2.29 = 1.178 x
\]
2. Now, we need to divide both sides by 1.178 to solve for \(x\):
\[
x = \frac{2.29}{1.178}
\]
3. Performing the division:
\[
x \approx 1.944
\]
4. Rounding to the nearest hundredth:
\[
x \approx 1.94
\]
Therefore, about **1.94 hours** of weekly aerobic activity will result in a 3-pound monthly weight loss.
1. We have the equation from his work:
\[
2.29 = 1.178 x
\]
2. Now, we need to divide both sides by 1.178 to solve for \(x\):
\[
x = \frac{2.29}{1.178}
\]
3. Performing the division:
\[
x \approx 1.944
\]
4. Rounding to the nearest hundredth:
\[
x \approx 1.94
\]
Therefore, about **1.94 hours** of weekly aerobic activity will result in a 3-pound monthly weight loss.