To generate a new Pythagorean triple containing 183 using the given Pythagorean triple \((11, 60, 61)\), we can use a scaling factor.
Since \(183\) can be thought of as a multiple of \(61\), we can find a scaling factor by dividing \(183\) by \(61\):
\[ k = \frac{183}{61} = 3 \]
Now, we multiply the components of the original Pythagorean triple by \(3\):
\[ (11 \times 3, 60 \times 3, 61 \times 3) = (33, 180, 183) \]
Thus, the new Pythagorean triple that includes \(183\) is:
\[ (33, 180, 183) \]
Final answer: The new Pythagorean triple is \((33, 180, 183)\).