Asked by julian celeste
Determine the zero(s) of the quadratic function y=−5x2+16x
.(1 point)
Responses
(0,5)(0,16)
left parenthesis 0 comma 5 right parenthesis left parenthesis 0 comma 16 right parenthesis
(0,0)(3.2,0)
left parenthesis 0 comma 0 right parenthesis left parenthesis 3.2 comma 0 right parenthesis
(−3.2,0)
left parenthesis negative 3.2 comma 0 right parenthesis
There are no zeros.
There are no zeros.
.(1 point)
Responses
(0,5)(0,16)
left parenthesis 0 comma 5 right parenthesis left parenthesis 0 comma 16 right parenthesis
(0,0)(3.2,0)
left parenthesis 0 comma 0 right parenthesis left parenthesis 3.2 comma 0 right parenthesis
(−3.2,0)
left parenthesis negative 3.2 comma 0 right parenthesis
There are no zeros.
There are no zeros.
Answers
Answered by
GPT-4o mini
To find the zeros of the quadratic function \( y = -5x^2 + 16x \), we need to set \( y \) equal to zero and solve for \( x \):
\[
-5x^2 + 16x = 0
\]
We can factor out \( x \) from the equation:
\[
x(-5x + 16) = 0
\]
Now, we have two cases to consider:
1. \( x = 0 \)
2. \( -5x + 16 = 0 \)
For the second case, we can solve for \( x \):
\[
-5x + 16 = 0 \implies -5x = -16 \implies x = \frac{16}{5} = 3.2
\]
Thus, the zeros of the quadratic function are:
\[
x = 0 \quad \text{and} \quad x = 3.2
\]
In coordinate form, the zeros are:
\[
(0, 0) \quad \text{and} \quad (3.2, 0)
\]
So the correct response is:
\((0, 0)(3.2, 0)\)
\[
-5x^2 + 16x = 0
\]
We can factor out \( x \) from the equation:
\[
x(-5x + 16) = 0
\]
Now, we have two cases to consider:
1. \( x = 0 \)
2. \( -5x + 16 = 0 \)
For the second case, we can solve for \( x \):
\[
-5x + 16 = 0 \implies -5x = -16 \implies x = \frac{16}{5} = 3.2
\]
Thus, the zeros of the quadratic function are:
\[
x = 0 \quad \text{and} \quad x = 3.2
\]
In coordinate form, the zeros are:
\[
(0, 0) \quad \text{and} \quad (3.2, 0)
\]
So the correct response is:
\((0, 0)(3.2, 0)\)
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