What is the solution of the equation βˆ’x2.9=βˆ’3.?

Answers

Answered by i πŸ’— πŸ§‹
So what’s the answer
Answered by i πŸ’— πŸ§‹
What is the solution of the equation βˆ’x/2.9=βˆ’3?
Answered by i πŸ’— πŸ§‹
What is the solution of the equationΒ  8/5xΒ =Β βˆ’10
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Good job bot πŸ‘
Answered by GPT-4o mini
To solve the equation \(-x^{2.9} = -3\), we can start by eliminating the negative signs on both sides. This gives us:

\[
x^{2.9} = 3
\]

Next, to solve for \(x\), we will need to raise both sides of the equation to the power of \(\frac{1}{2.9}\):

\[
x = 3^{\frac{1}{2.9}}
\]

Using a calculator, we can compute \(3^{\frac{1}{2.9}}\):

\[
x \approx 1.360
\]

Since \(x^{2.9}\) can also yield a negative value (because \(x\) can be negative), we should also consider the negative root:

\[
x = -3^{\frac{1}{2.9}} \approx -1.360
\]

Thus, the solutions for the equation \(-x^{2.9} = -3\) are:

\[
x \approx 1.360 \quad \text{and} \quad x \approx -1.360
\]
Answered by GPT-4o mini
The solutions to the equation \(-x^{2.9} = -3\) are:

\[
x \approx 1.360 \quad \text{and} \quad x \approx -1.360
\]

In summary, the two answers are:
1. \(x \approx 1.360\)
2. \(x \approx -1.360\)
Answered by GPT-4o mini
To solve the equation

\[
-\frac{x}{2.9} = -3,
\]

we can first eliminate the negative signs on both sides:

\[
\frac{x}{2.9} = 3.
\]

Next, to solve for \(x\), we can multiply both sides by \(2.9\):

\[
x = 3 \times 2.9.
\]

Calculating the right side:

\[
x = 8.7.
\]

Thus, the solution to the equation is

\[
\boxed{8.7}.
\]
Answered by GPT-4o mini
To solve the equation

\[
\frac{8}{5}x = -10,
\]

we can start by isolating \(x\). First, multiply both sides by \(\frac{5}{8}\) to get rid of the fraction:

\[
x = -10 \cdot \frac{5}{8}.
\]

Now, calculate the right side:

\[
x = -\frac{50}{8}.
\]

Simplifying \(-\frac{50}{8}\):

\[
x = -\frac{25}{4}.
\]

Thus, the solution to the equation is

\[
\boxed{-\frac{25}{4}} \quad \text{or} \quad -6.25.
\]
Answered by GPT-4o mini
Thank you! I'm glad I could help. If you have any more questions or need further assistance, feel free to ask! πŸ‘

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