Question
If a car slows from 60 m/s to 45 m/s in a period of 5.0 s, what was the average acceleration?
Group of answer choices
-60 m/s2
15 m/s2
-45 m/s2
-3 m/s2
Group of answer choices
-60 m/s2
15 m/s2
-45 m/s2
-3 m/s2
Answers
GPT-4o mini
To find the average acceleration, you can use the formula:
\[
a = \frac{\Delta v}{\Delta t}
\]
where:
- \( \Delta v \) is the change in velocity,
- \( \Delta t \) is the change in time.
In this case:
- Initial velocity (\( v_i \)) = 60 m/s
- Final velocity (\( v_f \)) = 45 m/s
- Change in time (\( \Delta t \)) = 5.0 s
First, calculate the change in velocity:
\[
\Delta v = v_f - v_i = 45 \, \text{m/s} - 60 \, \text{m/s} = -15 \, \text{m/s}
\]
Now plug this value into the acceleration formula:
\[
a = \frac{\Delta v}{\Delta t} = \frac{-15 \, \text{m/s}}{5.0 \, \text{s}} = -3 \, \text{m/s}^2
\]
Thus, the average acceleration is:
\(-3 \, \text{m/s}^2\)
The correct answer is:
**-3 m/s²**
\[
a = \frac{\Delta v}{\Delta t}
\]
where:
- \( \Delta v \) is the change in velocity,
- \( \Delta t \) is the change in time.
In this case:
- Initial velocity (\( v_i \)) = 60 m/s
- Final velocity (\( v_f \)) = 45 m/s
- Change in time (\( \Delta t \)) = 5.0 s
First, calculate the change in velocity:
\[
\Delta v = v_f - v_i = 45 \, \text{m/s} - 60 \, \text{m/s} = -15 \, \text{m/s}
\]
Now plug this value into the acceleration formula:
\[
a = \frac{\Delta v}{\Delta t} = \frac{-15 \, \text{m/s}}{5.0 \, \text{s}} = -3 \, \text{m/s}^2
\]
Thus, the average acceleration is:
\(-3 \, \text{m/s}^2\)
The correct answer is:
**-3 m/s²**