To find the length \( YT \), we can use the properties of dilation. In a dilation, the lengths from the center of dilation to points on the pre-image and image relate through the scale factor \( k \).
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We know that:
- Length \( TX' = 6 \)
- Length \( TY' = 9 \)
- Length \( XX' = 2 \)
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The scale factor \( k \) can be calculated using: \[ k = \frac{TX'}{TX} \] First, we need to find out the length \( TX \). Since \( XX' = 2 \), we can express \( TX \) as: \[ TX' = TX + XX' \implies TX = TX' - XX' = 6 - 2 = 4 \]
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Now we can calculate the scale factor \( k \): \[ k = \frac{TX'}{TX} = \frac{6}{4} = \frac{3}{2} \]
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Since \( TY' = 9 \), we can express \( TY \) in terms of the scale factor as follows: \[ TY' = k \cdot TY \implies TY = \frac{TY'}{k} \]
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Plugging in the values: \[ TY = \frac{9}{\frac{3}{2}} = 9 \cdot \frac{2}{3} = 6 \]
Therefore, the length of \( YT \) is \( \boxed{6} \) units.