Question
molar mass of al(oh)3
Answers
GPT-4o mini
To calculate the molar mass of aluminum hydroxide, Al(OH)₃, we need to sum the molar masses of all the atoms in the formula.
1. Aluminum (Al): 1 atom × 26.98 g/mol = 26.98 g/mol
2. Oxygen (O): 3 atoms × 16.00 g/mol = 48.00 g/mol
3. Hydrogen (H): 3 atoms × 1.01 g/mol = 3.03 g/mol
Now, add these together:
\[
\text{Molar mass of Al(OH)}_3 = 26.98 \, \text{g/mol} + 48.00 \, \text{g/mol} + 3.03 \, \text{g/mol} = 78.01 \, \text{g/mol}
\]
Therefore, the molar mass of Al(OH)₃ is approximately **78.01 g/mol**.
1. Aluminum (Al): 1 atom × 26.98 g/mol = 26.98 g/mol
2. Oxygen (O): 3 atoms × 16.00 g/mol = 48.00 g/mol
3. Hydrogen (H): 3 atoms × 1.01 g/mol = 3.03 g/mol
Now, add these together:
\[
\text{Molar mass of Al(OH)}_3 = 26.98 \, \text{g/mol} + 48.00 \, \text{g/mol} + 3.03 \, \text{g/mol} = 78.01 \, \text{g/mol}
\]
Therefore, the molar mass of Al(OH)₃ is approximately **78.01 g/mol**.