Question
A sound wave of wavelength 0.60 m and velocity 620 m/s is produced for 0.50 s. What is the frequency of the wave?
Group of answer choices
2,066 s−1
310 s−1
470 s−1
1,033 s−1
Group of answer choices
2,066 s−1
310 s−1
470 s−1
1,033 s−1
Answers
Answered by
GPT-4o mini
To determine the frequency of a sound wave, we can use the formula:
\[
f = \frac{v}{\lambda}
\]
where:
- \( f \) is the frequency in hertz (Hz), which is equivalent to s\(^{-1}\),
- \( v \) is the velocity of the wave (620 m/s in this case),
- \( \lambda \) (lambda) is the wavelength (0.60 m in this case).
Now we can substitute the values into the formula:
\[
f = \frac{620 \, \text{m/s}}{0.60 \, \text{m}}
\]
Calculating this gives:
\[
f = \frac{620}{0.60} = 1033.33 \, \text{s}^{-1}
\]
Rounding to three significant figures, we get:
\[
f \approx 1,033 \, \text{s}^{-1}
\]
Thus, the frequency of the wave is **1,033 s\(^{-1}\)**.
The correct answer is **1,033 s\(^{-1}\)**.
\[
f = \frac{v}{\lambda}
\]
where:
- \( f \) is the frequency in hertz (Hz), which is equivalent to s\(^{-1}\),
- \( v \) is the velocity of the wave (620 m/s in this case),
- \( \lambda \) (lambda) is the wavelength (0.60 m in this case).
Now we can substitute the values into the formula:
\[
f = \frac{620 \, \text{m/s}}{0.60 \, \text{m}}
\]
Calculating this gives:
\[
f = \frac{620}{0.60} = 1033.33 \, \text{s}^{-1}
\]
Rounding to three significant figures, we get:
\[
f \approx 1,033 \, \text{s}^{-1}
\]
Thus, the frequency of the wave is **1,033 s\(^{-1}\)**.
The correct answer is **1,033 s\(^{-1}\)**.
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