Asked by annoymous
The content includes measurements of 4 m, 10 m, and 7 m represented in a diagram. It appears to be a drawing or illustration that visually conveys these dimensions. The tags indicate that this may be cartoon-like or clipart in style.
Find the volume of the cylinder, in cubic meters. Use 3.14 for pi. Round your answer to the nearest hundredth.(1 point)
Find the volume of the cylinder, in cubic meters. Use 3.14 for pi. Round your answer to the nearest hundredth.(1 point)
Answers
Answered by
GPT-4o mini
To find the volume of a cylinder, we use the formula:
\[
V = \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
From your description, I assume that:
- The height of the cylinder is given as 10 m.
- The diameter of the cylinder (which I will assume is represented by one of the other measurements) is 7 m. Therefore, the radius \( r \) would be half of the diameter.
Calculating the radius:
\[
r = \frac{d}{2} = \frac{7 \, \text{m}}{2} = 3.5 \, \text{m}
\]
Now, substituting the values of \( r \) and \( h \) into the volume formula:
\[
V = 3.14 \times (3.5 \, \text{m})^2 \times 10 \, \text{m}
\]
Calculating \( (3.5)^2 \):
\[
(3.5)^2 = 12.25
\]
Now substituting back to the volume equation:
\[
V = 3.14 \times 12.25 \times 10
\]
Calculating \( 3.14 \times 12.25 \):
\[
3.14 \times 12.25 = 38.675
\]
Now multiplying by the height \( 10 \):
\[
V = 38.675 \times 10 = 386.75
\]
Thus, rounding to the nearest hundredth:
\[
\boxed{386.75} \, \text{cubic meters}
\]
\[
V = \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
From your description, I assume that:
- The height of the cylinder is given as 10 m.
- The diameter of the cylinder (which I will assume is represented by one of the other measurements) is 7 m. Therefore, the radius \( r \) would be half of the diameter.
Calculating the radius:
\[
r = \frac{d}{2} = \frac{7 \, \text{m}}{2} = 3.5 \, \text{m}
\]
Now, substituting the values of \( r \) and \( h \) into the volume formula:
\[
V = 3.14 \times (3.5 \, \text{m})^2 \times 10 \, \text{m}
\]
Calculating \( (3.5)^2 \):
\[
(3.5)^2 = 12.25
\]
Now substituting back to the volume equation:
\[
V = 3.14 \times 12.25 \times 10
\]
Calculating \( 3.14 \times 12.25 \):
\[
3.14 \times 12.25 = 38.675
\]
Now multiplying by the height \( 10 \):
\[
V = 38.675 \times 10 = 386.75
\]
Thus, rounding to the nearest hundredth:
\[
\boxed{386.75} \, \text{cubic meters}
\]
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