To find the equation of the line that passes through the points \((-3, 4)\) and \((-6, 3)\), we will first calculate the slope \(m\) using the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Let \((x_1, y_1) = (-3, 4)\) and \((x_2, y_2) = (-6, 3)\):
\[ m = \frac{3 - 4}{-6 - (-3)} = \frac{-1}{-6 + 3} = \frac{-1}{-3} = \frac{1}{3} \]
Now that we have the slope \(m = \frac{1}{3}\), we can use the point-slope form of the equation of a line:
\[ y - y_1 = m(x - x_1) \]
We'll use the point \((-3, 4)\):
\[ y - 4 = \frac{1}{3}(x + 3) \]
Now, distribute the slope on the right-hand side:
\[ y - 4 = \frac{1}{3}x + 1 \]
Now, add \(4\) to both sides to solve for \(y\):
\[ y = \frac{1}{3}x + 1 + 4 \] \[ y = \frac{1}{3}x + 5 \]
Thus, the equation of the line in slope-intercept form is:
\[ y = \frac{1}{3}x + 5 \]