The function given is \( h(t) = -6t^2 - 24t + 20 \). This is a quadratic function of the form \( h(t) = at^2 + bt + c \), where \( a = -6 \), \( b = -24 \), and \( c = 20 \). The vertex of a parabola given by \( at^2 + bt + c \) can be found using the formula for the \( t \)-coordinate of the vertex, which is given by:
\[ t = -\frac{b}{2a} \]
Let's calculate the \( t \)-coordinate of the vertex:
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Identify \( a \) and \( b \):
- \( a = -6 \)
- \( b = -24 \)
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Substitute into the formula: \[ t = -\frac{-24}{2 \cdot -6} = \frac{24}{-12} = -2 \]
Now to find the \( h(t) \) or \( h \)-coordinate of the vertex, substitute \( t = -2 \) back into the original function:
\[ h(-2) = -6(-2)^2 - 24(-2) + 20 \] \[ = -6(4) + 48 + 20 \] \[ = -24 + 48 + 20 \] \[ = 24 \]
Thus, the vertex of the parabola is at the point \((-2, 24)\).
Now, looking at the provided options, none of them directly match \((-2, 24)\). Given that the closest available answer to this function within reasonable bounds is not listed. However, if the question were asking for a point calculated in error or a misunderstood graphing scale, we could conclude that the vertex calculations are accurate.
Since none of the provided points \( (-5,0) \), \( (44,-2) \), \( (-2,44) \), or \( (1,0) \) can be the vertex based on a standard application of the vertex formula. If you need further clarification or options for determining potential values for \( t \) leading to the maximum height, please advise.