To determine which ordered pairs are solutions to the equation \( 8 - 2y = 4x^2 \), we'll substitute each pair into the equation and see if they satisfy it.
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For Option #1: \( (0, 8) \)
- Substitute \( x = 0 \) and \( y = 8 \): \[ 8 - 2(8) = 4(0^2) \] \[ 8 - 16 = 0 \] \[ -8 \neq 0 \] So, Option #1 is not a solution.
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For Option #2: \( (-1, 2) \)
- Substitute \( x = -1 \) and \( y = 2 \): \[ 8 - 2(2) = 4(-1^2) \] \[ 8 - 4 = 4(1) \] \[ 4 = 4 \] So, Option #2 is a solution.
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For Option #3: \( (4, 0) \)
- Substitute \( x = 4 \) and \( y = 0 \): \[ 8 - 2(0) = 4(4^2) \] \[ 8 = 4(16) \] \[ 8 = 64 \] So, Option #3 is not a solution.
Based on the calculations above, the ordered pair that is a solution to the equation is Option #2: (-1, 2).