Asked by ~christina~
A ball was hit over a net
Vy= 0
Soy= 2.37m
g= -9.8
Vox= 34.42m/s
t= 2.137
Sx= 23.92m
I know the equations used are
Sx= (34.42m/s)t
Sy= 2.37m + 1/2(-9.8)t^2
using:
Sx= Soy + Vxt
Sy= Soy + Vyt + 0.5gt^2
if I'm not incorrect...I plugged in the values and made 2 displacement graphs with respect to time.
How would I go and make a velocity vs time graph for the x component and y component??
Do I go and get the derivative of the eequation or something?
Vy= 0
Soy= 2.37m
g= -9.8
Vox= 34.42m/s
t= 2.137
Sx= 23.92m
I know the equations used are
Sx= (34.42m/s)t
Sy= 2.37m + 1/2(-9.8)t^2
using:
Sx= Soy + Vxt
Sy= Soy + Vyt + 0.5gt^2
if I'm not incorrect...I plugged in the values and made 2 displacement graphs with respect to time.
How would I go and make a velocity vs time graph for the x component and y component??
Do I go and get the derivative of the eequation or something?
Answers
Answered by
bobpursley
I would just take the derivative of each, and plot them on the same graph (different colors?) vs time.
Answered by
drwls
Vx = Vox at all times
Vy = Voy - gt, but in your case Voy = 0, so
Vy = -gt
(until the ball hits the ground)
Vy = Voy - gt, but in your case Voy = 0, so
Vy = -gt
(until the ball hits the ground)
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